1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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Question

$$( 3 ^ { - 1 } \times 9 ^ { - 1 } ) \div 3 ^ { - 2 }$$

$\frac{1}{3}\approx 0.333333333$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$3^{1}\times \frac{1}{9}$$

Express $3^{1}\times \frac{1}{9}$ as a single fraction.

$$\frac{3^{1}}{9}$$

Calculate $3$ to the power of $1$ and get $3$.

$$\frac{3}{9}$$

Reduce the fraction $\frac{3}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{3}$$

$\frac{1}{3} = 0.3333333333333333$