$$(3\sqrt{3}-2\sqrt{2})(4\sqrt{2}\times2\sqrt{3})$$
$72\sqrt{2}-32\sqrt{3}\approx 46.397750649$
$$\left(3\sqrt{3}-2\sqrt{2}\right)\times 8\sqrt{2}\sqrt{3}$$
$$\left(3\sqrt{3}-2\sqrt{2}\right)\times 8\sqrt{6}$$
$$\left(24\sqrt{3}-16\sqrt{2}\right)\sqrt{6}$$
$$24\sqrt{3}\sqrt{6}-16\sqrt{2}\sqrt{6}$$
$$24\sqrt{3}\sqrt{3}\sqrt{2}-16\sqrt{2}\sqrt{6}$$
$$24\times 3\sqrt{2}-16\sqrt{2}\sqrt{6}$$
$$72\sqrt{2}-16\sqrt{2}\sqrt{6}$$
$$72\sqrt{2}-16\sqrt{2}\sqrt{2}\sqrt{3}$$
$$72\sqrt{2}-16\times 2\sqrt{3}$$
$$72\sqrt{2}-32\sqrt{3}$$
Show Solution
Hide Solution
