$$(3\sqrt{7}+4\sqrt{7}-3\sqrt{3})\sqrt{7}$$
$49-3\sqrt{21}\approx 35.252272915$
$$\left(7\sqrt{7}-3\sqrt{3}\right)\sqrt{7}$$
$$7\left(\sqrt{7}\right)^{2}-3\sqrt{3}\sqrt{7}$$
$$7\times 7-3\sqrt{3}\sqrt{7}$$
$$49-3\sqrt{3}\sqrt{7}$$
$$49-3\sqrt{21}$$
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