Simplify \({4}^{2}\) to \(16\).
\[{(3x+2)}^{2}=9{x}^{2}+16+12x\]
Expand.
\[9{x}^{2}+12x+4=9{x}^{2}+16+12x\]
Cancel \(9{x}^{2}\) on both sides.
\[12x+4=16+12x\]
Cancel \(12x\) on both sides.
\[4=16\]
Since \(4=16\) is false, there is no solution.
[No Solution]
