$$(3a+7)+(6a-2)$$
$9a+5$
$$9a+7-2$$
$$9a+5$$
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$9$
$$\frac{\mathrm{d}}{\mathrm{d}a}(9a+7-2)$$
$$\frac{\mathrm{d}}{\mathrm{d}a}(9a+5)$$
$$9a^{1-1}$$
$$9a^{0}$$
$$9\times 1$$
$$9$$