$$(3n-4)(4x+1); 12nx+3n-16-4$$
$\left(3n-4\right)\left(4x+1\right)\left(12nx+3n-20\right)$
$$\left(3n-4\right)\left(4x+1\right)\left(12nx+3n-20\right)$$
$$144n^{2}x^{2}-192nx^{2}+72xn^{2}-336nx+320x+9n^{2}-72n+80$$
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$\left(3n-4\right)\left(4x+1\right),\ 12nx+3n-20$
