$$(3x-1,2)=(2,y+1)$$
$x=\frac{2y}{3}+\frac{11}{15}$
$$3x=2y+1+1,2$$
$$3x=2y+2,2$$
$$\frac{3x}{3}=\frac{2y+2,2}{3}$$
$$x=\frac{2y+2,2}{3}$$
$$x=\frac{2y}{3}+\frac{11}{15}$$
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$y=\frac{3x}{2}-1,1$
$$2y+1=3x-1,2$$
$$2y=3x-1,2-1$$
$$2y=3x-2,2$$
$$\frac{2y}{2}=\frac{3x-2,2}{2}$$
$$y=\frac{3x-2,2}{2}$$
$$y=\frac{3x}{2}-\frac{11}{10}$$
