Solve (3x-2)+(6x+3)= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(3x-2)+(6x+3)=$$

Evaluate

$9x+1$

Differentiate w.r.t. x

$9$

Steps Using Derivative Rule for Sum

Combine $3x$ and $6x$ to get $9x$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x-2+3)$$

Add $-2$ and $3$ to get $1$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(9x+1)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$9x^{1-1}$$

Subtract $1$ from $1$.

$$9x^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$9\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$9$$