Question

$$(3x+2)/3+1=(x-3)/6$$

Answer

x=-13/5

Solution


Multiply both sides by \(6\) (the LCM of \(3, 6\)).
\[2(3x+2)+6=x-3\]
Expand.
\[6x+4+6=x-3\]
Simplify  \(6x+4+6\)  to  \(6x+10\).
\[6x+10=x-3\]
Subtract \(x\) from both sides.
\[6x+10-x=-3\]
Simplify  \(6x+10-x\)  to  \(5x+10\).
\[5x+10=-3\]
Subtract \(10\) from both sides.
\[5x=-3-10\]
Simplify  \(-3-10\)  to  \(-13\).
\[5x=-13\]
Divide both sides by \(5\).
\[x=-\frac{13}{5}\]

Decimal Form: -2.6