How to solve (3x+y-5)(3x-y-5)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (3x+y-5)(3x-y-5) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(3x+y-5)(3x-y-5)$$

Evaluate

$\left(3x-5\right)^{2}-y^{2}$

Solution Steps

Apply the distributive property by multiplying each term of $3x+y-5$ by each term of $3x-y-5$.

$$9x^{2}-3xy-15x+3yx-y^{2}-5y-15x+5y+25$$

Combine $-3xy$ and $3yx$ to get $0$.

$$9x^{2}-15x-y^{2}-5y-15x+5y+25$$

Combine $-15x$ and $-15x$ to get $-30x$.

$$9x^{2}-30x-y^{2}-5y+5y+25$$

Combine $-5y$ and $5y$ to get $0$.

$$9x^{2}-30x-y^{2}+25$$

Show Solution

Expand

$9x^{2}-30x-y^{2}+25$

Solution Steps

Apply the distributive property by multiplying each term of $3x+y-5$ by each term of $3x-y-5$.

$$9x^{2}-3xy-15x+3yx-y^{2}-5y-15x+5y+25$$

Combine $-3xy$ and $3yx$ to get $0$.

$$9x^{2}-15x-y^{2}-5y-15x+5y+25$$

Combine $-15x$ and $-15x$ to get $-30x$.

$$9x^{2}-30x-y^{2}-5y+5y+25$$

Combine $-5y$ and $5y$ to get $0$.

$$9x^{2}-30x-y^{2}+25$$

Show Solution

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Example

Question

Evaluate

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Solution Steps