$$(3x^{3}+4x^{2}+5x+18)\div(x+2)$$
$3x^{2}-2x+9$
$$\frac{3\left(x+2\right)\left(x^{2}-\frac{2}{3}x+3\right)}{x+2}$$
$$3\left(x^{2}-\frac{2}{3}x+3\right)$$
$$3x^{2}-2x+9$$
Show Solution
Hide Solution