How to solve (3x ^ 3 * y) ^ 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (3x ^ 3 * y) ^ 2 | Equatix

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Question

$$(3x^{3}y)^{2}$$

Evaluate

$9y^{2}x^{6}$

Solution Steps

Use the rules of exponents to simplify the expression.

$$\left(3x^{3}y^{1}\right)^{2}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$3^{2}\left(x^{3}\right)^{2}\left(y^{1}\right)^{2}$$

Raise $3$ to the power $2$.

$$9\left(x^{3}\right)^{2}\left(y^{1}\right)^{2}$$

To raise a power to another power, multiply the exponents.

$$9x^{3\times 2}y^{2}$$

Multiply $3$ times $2$.

$$9x^{6}y^{2}$$

Show Solution

Expand

$9y^{2}x^{6}$

Solution Steps

Use the rules of exponents to simplify the expression.

$$\left(3x^{3}y^{1}\right)^{2}$$

To raise the product of two or more numbers to a power, raise each number to the power and take their product.

$$3^{2}\left(x^{3}\right)^{2}\left(y^{1}\right)^{2}$$

Raise $3$ to the power $2$.

$$9\left(x^{3}\right)^{2}\left(y^{1}\right)^{2}$$

To raise a power to another power, multiply the exponents.

$$9x^{3\times 2}y^{2}$$

Multiply $3$ times $2$.

$$9x^{6}y^{2}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

Statistics

Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

Solution Steps

Expand

Solution Steps