Question

$$(4 { x }^{ 2 } -12 \times ) \times ( { 6 }^{ 2 } -12)=0$$

Answer

x=sqrt(3),-sqrt(3)

Solution


Simplify  \({6}^{2}\)  to  \(36\).
\[(4{x}^{2}-12)(36-12)=0\]
Simplify  \(36-12\)  to  \(24\).
\[(4{x}^{2}-12)\times 24=0\]
Regroup terms.
\[24(4{x}^{2}-12)=0\]
Divide both sides by \(24\).
\[4{x}^{2}-12=0\]
Add \(12\) to both sides.
\[4{x}^{2}=12\]
Divide both sides by \(4\).
\[{x}^{2}=\frac{12}{4}\]
Take the square root of both sides.
\[x=\pm \sqrt{\frac{12}{4}}\]
Simplify  \(\sqrt{\frac{12}{4}}\)  to  \(\frac{\sqrt{12}}{\sqrt{4}}\).
\[x=\pm \frac{\sqrt{12}}{\sqrt{4}}\]
Use this rule: \(\sqrt{ab}=\sqrt{a}\sqrt{b}\).
\[x=\pm \frac{\sqrt{12}\sqrt{1}}{\sqrt{4}}\]
Simplify  \(\sqrt{12}\)  to  \(2\sqrt{3}\).
\[x=\pm \frac{2\sqrt{3}\sqrt{1}}{\sqrt{4}}\]
Simplify  \(\sqrt{1}\)  to  \(1\).
\[x=\pm \frac{2\sqrt{3}\times 1}{\sqrt{4}}\]
Simplify  \(2\sqrt{3}\times 1\)  to  \(2\sqrt{3}\).
\[x=\pm \frac{2\sqrt{3}}{\sqrt{4}}\]
Since \(2\times 2=4\), the square root of \(4\) is \(2\).
\[x=\pm \frac{2\sqrt{3}}{2}\]
Cancel \(2\).
\[x=\pm \sqrt{3}\]

Decimal Form: ±1.732051