$$(4+10-3) \times 2+(100+22 \div 2)=3]$$
$\text{false}$
$$\left(14-3\right)\times 2+100+\frac{22}{2}=3$$
$$11\times 2+100+\frac{22}{2}=3$$
$$22+100+\frac{22}{2}=3$$
$$122+\frac{22}{2}=3$$
$$122+11=3$$
$$133=3$$
$$\text{false}$$
Show Solution
Hide Solution