How to solve (45-55)+(71-93)6

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (45-55)+(71-93)6 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(45-55)+(71-93)6$$

Evaluate

$-142$

Solution Steps

Subtract $55$ from $45$ to get $-10$.

$$-10+\left(71-93\right)\times 6$$

Subtract $93$ from $71$ to get $-22$.

$$-10-22\times 6$$

Multiply $-22$ and $6$ to get $-132$.

$$-10-132$$

Subtract $132$ from $-10$ to get $-142$.

$$-142$$

Show Solution

Factor

$-142$

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