Solve (4x-1)(3x+5)-(x-7) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(4x-1)(3x+5)-(x-7)$$

Evaluate

$12x^{2}+16x+2$

Solution Steps

Apply the distributive property by multiplying each term of $4x-1$ by each term of $3x+5$.

$$12x^{2}+20x-3x-5-\left(x-7\right)$$

Combine $20x$ and $-3x$ to get $17x$.

$$12x^{2}+17x-5-\left(x-7\right)$$

To find the opposite of $x-7$, find the opposite of each term.

$$12x^{2}+17x-5-x-\left(-7\right)$$

The opposite of $-7$ is $7$.

$$12x^{2}+17x-5-x+7$$

Combine $17x$ and $-x$ to get $16x$.

$$12x^{2}+16x-5+7$$

Add $-5$ and $7$ to get $2$.

$$12x^{2}+16x+2$$

Expand

$12x^{2}+16x+2$

Solution Steps

Apply the distributive property by multiplying each term of $4x-1$ by each term of $3x+5$.

$$12x^{2}+20x-3x-5-\left(x-7\right)$$

Combine $20x$ and $-3x$ to get $17x$.

$$12x^{2}+17x-5-\left(x-7\right)$$

To find the opposite of $x-7$, find the opposite of each term.

$$12x^{2}+17x-5-x-\left(-7\right)$$

The opposite of $-7$ is $7$.

$$12x^{2}+17x-5-x+7$$

Combine $17x$ and $-x$ to get $16x$.

$$12x^{2}+16x-5+7$$

Add $-5$ and $7$ to get $2$.

$$12x^{2}+16x+2$$