$$(4y+20) \times ( \frac{ 3 }{ 4 } )$$
$3\left(y+5\right)$
$$4y\times \frac{3}{4}+20\times \frac{3}{4}$$
$$3y+20\times \frac{3}{4}$$
$$3y+\frac{20\times 3}{4}$$
$$3y+\frac{60}{4}$$
$$3y+15$$
Show Solution
Hide Solution
$3y+15$
