Solve (5/2+7/5)=(7/5+5/2 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(5/2+7/5)=(7/5+5/2$$

Verify

$\text{true}$

Solution Steps

Least common multiple of $2$ and $5$ is $10$. Convert $\frac{5}{2}$ and $\frac{7}{5}$ to fractions with denominator $10$.

$$\frac{25}{10}+\frac{14}{10}=\frac{7}{5}+\frac{5}{2}$$

Since $\frac{25}{10}$ and $\frac{14}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{25+14}{10}=\frac{7}{5}+\frac{5}{2}$$

Add $25$ and $14$ to get $39$.

$$\frac{39}{10}=\frac{7}{5}+\frac{5}{2}$$

Least common multiple of $5$ and $2$ is $10$. Convert $\frac{7}{5}$ and $\frac{5}{2}$ to fractions with denominator $10$.

$$\frac{39}{10}=\frac{14}{10}+\frac{25}{10}$$

Since $\frac{14}{10}$ and $\frac{25}{10}$ have the same denominator, add them by adding their numerators.

$$\frac{39}{10}=\frac{14+25}{10}$$

Add $14$ and $25$ to get $39$.

$$\frac{39}{10}=\frac{39}{10}$$

Compare $\frac{39}{10}$ and $\frac{39}{10}$.

$$\text{true}$$