How to solve (5-9+(7*2^ 2 -8)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (5-9+(7*2^ 2 -8) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(5-9+(7\times2^{2}-8)$$

Evaluate

$16$

Solution Steps

Subtract $9$ from $5$ to get $-4$.

$$-4+7\times 2^{2}-8$$

Calculate $2$ to the power of $2$ and get $4$.

$$-4+7\times 4-8$$

Multiply $7$ and $4$ to get $28$.

$$-4+28-8$$

Add $-4$ and $28$ to get $24$.

$$24-8$$

Subtract $8$ from $24$ to get $16$.

$$16$$

Show Solution

Factor

$2^{4}$

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