$$(5-n):\frac{n^{2}-25}{7}$$
$-\frac{7}{n+5}$
$$\frac{\left(5-n\right)\times 7}{n^{2}-25}$$
$$\frac{7\left(-n+5\right)}{\left(n-5\right)\left(n+5\right)}$$
$$\frac{-7\left(n-5\right)}{\left(n-5\right)\left(n+5\right)}$$
$$\frac{-7}{n+5}$$
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