Question

$$(5^{0}+4^{-1}); \times2^{2}$$

Answer

$$1+4^-1;*4$$

Solution


Use Rule of Zero: \({x}^{0}=1\).
\[\begin{aligned}&1+{4}^{-1}\\&\times {2}^{2}\end{aligned}\]
Simplify  \({2}^{2}\)  to  \(4\).
\[\begin{aligned}&1+{4}^{-1}\\&\times 4\end{aligned}\]