$$[(5^{4}\cdot5^{2}):5^{3}]^{2}:5^{4}-5\cdot4+2^{2}\cdot3^{2}-(5^{2}\cdot3^{2})^{0}$$
$40$
$$\frac{\left(\frac{5^{6}}{5^{3}}\right)^{2}}{5^{4}}-5\times 4+2^{2}\times 3^{2}-\left(5^{2}\times 3^{2}\right)^{0}$$
$$\frac{\left(5^{3}\right)^{2}}{5^{4}}-5\times 4+2^{2}\times 3^{2}-\left(5^{2}\times 3^{2}\right)^{0}$$
$$\frac{5^{6}}{5^{4}}-5\times 4+2^{2}\times 3^{2}-\left(5^{2}\times 3^{2}\right)^{0}$$
$$5^{2}-5\times 4+2^{2}\times 3^{2}-\left(5^{2}\times 3^{2}\right)^{0}$$
$$25-5\times 4+2^{2}\times 3^{2}-\left(5^{2}\times 3^{2}\right)^{0}$$
$$25-20+2^{2}\times 3^{2}-\left(5^{2}\times 3^{2}\right)^{0}$$
$$5+2^{2}\times 3^{2}-\left(5^{2}\times 3^{2}\right)^{0}$$
$$5+4\times 3^{2}-\left(5^{2}\times 3^{2}\right)^{0}$$
$$5+4\times 9-\left(5^{2}\times 3^{2}\right)^{0}$$
$$5+36-\left(5^{2}\times 3^{2}\right)^{0}$$
$$41-\left(5^{2}\times 3^{2}\right)^{0}$$
$$41-\left(25\times 3^{2}\right)^{0}$$
$$41-\left(25\times 9\right)^{0}$$
$$41-225^{0}$$
$$41-1$$
$$40$$
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$2^{3}\times 5$