$$[(55-10)-(3 \times 6 \times 9)]/(-3)$$
$39$
$$\frac{45-3\times 6\times 9}{-3}$$
$$\frac{45-18\times 9}{-3}$$
$$\frac{45-162}{-3}$$
$$\frac{-117}{-3}$$
$$39$$
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$3\times 13$
