Solve (5c + 26c + 20) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(5c+26c+20)$$

Differentiate w.r.t. c

$31$

Steps Using Derivative Rule for Sum

Combine $5c$ and $26c$ to get $31c$.

$$\frac{\mathrm{d}}{\mathrm{d}c}(31c+20)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$31c^{1-1}$$

Subtract $1$ from $1$.

$$31c^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$31\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$31$$

Evaluate

$31c+20$