$$(6\frac{1}{3}-4\frac{5}{9})\cdot(\frac{3}{7}+2\frac{1}{21})$$
$\frac{832}{189}\approx 4.402116402$
$$\left(\frac{18+1}{3}-\frac{4\times 9+5}{9}\right)\left(\frac{3}{7}+\frac{2\times 21+1}{21}\right)$$
$$\left(\frac{19}{3}-\frac{4\times 9+5}{9}\right)\left(\frac{3}{7}+\frac{2\times 21+1}{21}\right)$$
$$\left(\frac{19}{3}-\frac{36+5}{9}\right)\left(\frac{3}{7}+\frac{2\times 21+1}{21}\right)$$
$$\left(\frac{19}{3}-\frac{41}{9}\right)\left(\frac{3}{7}+\frac{2\times 21+1}{21}\right)$$
$$\left(\frac{57}{9}-\frac{41}{9}\right)\left(\frac{3}{7}+\frac{2\times 21+1}{21}\right)$$
$$\frac{57-41}{9}\left(\frac{3}{7}+\frac{2\times 21+1}{21}\right)$$
$$\frac{16}{9}\left(\frac{3}{7}+\frac{2\times 21+1}{21}\right)$$
$$\frac{16}{9}\left(\frac{3}{7}+\frac{42+1}{21}\right)$$
$$\frac{16}{9}\left(\frac{3}{7}+\frac{43}{21}\right)$$
$$\frac{16}{9}\left(\frac{9}{21}+\frac{43}{21}\right)$$
$$\frac{16}{9}\times \frac{9+43}{21}$$
$$\frac{16}{9}\times \frac{52}{21}$$
$$\frac{16\times 52}{9\times 21}$$
$$\frac{832}{189}$$
Show Solution
Hide Solution
$\frac{2 ^ {6} \cdot 13}{3 ^ {3} \cdot 7} = 4\frac{76}{189} = 4.402116402116402$
