Solve (6-4)+3-18+31-(+4+10)= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(6-4)+3-18+31-(+4+10)=$$

Evaluate

$4$

Solution Steps

Subtract $4$ from $6$ to get $2$.

$$2+3-18+31-\left(4+10\right)$$

Add $2$ and $3$ to get $5$.

$$5-18+31-\left(4+10\right)$$

Subtract $18$ from $5$ to get $-13$.

$$-13+31-\left(4+10\right)$$

Add $-13$ and $31$ to get $18$.

$$18-\left(4+10\right)$$

Add $4$ and $10$ to get $14$.

$$18-14$$

Subtract $14$ from $18$ to get $4$.

$$4$$

Factor

$2^{2}$