Solve (6x + 2) - 3x ^ 8 + 6 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(6x+2)-3x^{8}+6$$

Differentiate w.r.t. x

$6-24x^{7}$

Steps Using Derivative Rule for Sum

Add $2$ and $6$ to get $8$.

$$\frac{\mathrm{d}}{\mathrm{d}x}(6x+8-3x^{8})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is $0$. The derivative of $ax^{n}$ is $nax^{n-1}$.

$$6x^{1-1}+8\left(-3\right)x^{8-1}$$

Subtract $1$ from $1$.

$$6x^{0}+8\left(-3\right)x^{8-1}$$

Multiply $8$ times $-3$.

$$6x^{0}-24x^{8-1}$$

Subtract $1$ from $8$.

$$6x^{0}-24x^{7}$$

For any term $t$ except $0$, $t^{0}=1$.

$$6\times 1-24x^{7}$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$6-24x^{7}$$

Evaluate

$8+6x-3x^{8}$