$$(6x^{2}+11x-35)\div(-2x-7)$$
$5-3x$
$$\frac{\left(3x-5\right)\left(2x+7\right)}{-2x-7}$$
$$\frac{-\left(-2x-7\right)\left(3x-5\right)}{-2x-7}$$
$$-\left(3x-5\right)$$
$$-3x+5$$
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