Solve (6x ^ 2 + 8x - 10) - (2x ^ 2 + 3x + 4) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(6x^{2}+8x-10)-(2x^{2}+3x+4)$$

Evaluate

$4x^{2}+5x-14$

Solution Steps

To find the opposite of $2x^{2}+3x+4$, find the opposite of each term.

$$6x^{2}+8x-10-2x^{2}-3x-4$$

Combine $6x^{2}$ and $-2x^{2}$ to get $4x^{2}$.

$$4x^{2}+8x-10-3x-4$$

Combine $8x$ and $-3x$ to get $5x$.

$$4x^{2}+5x-10-4$$

Subtract $4$ from $-10$ to get $-14$.

$$4x^{2}+5x-14$$

Expand

$4x^{2}+5x-14$

Solution Steps

To find the opposite of $2x^{2}+3x+4$, find the opposite of each term.

$$6x^{2}+8x-10-2x^{2}-3x-4$$

Combine $6x^{2}$ and $-2x^{2}$ to get $4x^{2}$.

$$4x^{2}+8x-10-3x-4$$

Combine $8x$ and $-3x$ to get $5x$.

$$4x^{2}+5x-10-4$$

Subtract $4$ from $-10$ to get $-14$.

$$4x^{2}+5x-14$$