How to solve (7/6)-(2/3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (7/6)-(2/3) | Equatix

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$$(7/6)-(2/3)$$

$\frac{1}{2}=0.5$

Least common multiple of $6$ and $3$ is $6$. Convert $\frac{7}{6}$ and $\frac{2}{3}$ to fractions with denominator $6$.

$$\frac{7}{6}-\frac{4}{6}$$

Since $\frac{7}{6}$ and $\frac{4}{6}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{7-4}{6}$$

Subtract $4$ from $7$ to get $3$.

$$\frac{3}{6}$$

Reduce the fraction $\frac{3}{6}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{2}$$

$\frac{1}{2} = 0.5$