How to solve (7-2+4)-(2-5)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (7-2+4)-(2-5) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(7-2+4)-(2-5)$$

Evaluate

$12$

Solution Steps

Subtract $2$ from $7$ to get $5$.

$$5+4-\left(2-5\right)$$

Add $5$ and $4$ to get $9$.

$$9-\left(2-5\right)$$

Subtract $5$ from $2$ to get $-3$.

$$9-\left(-3\right)$$

The opposite of $-3$ is $3$.

$$9+3$$

Add $9$ and $3$ to get $12$.

$$12$$

Show Solution

Factor

$2^{2}\times 3$

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