Solve (7-3+6)-(-5-8)+14+3= | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(7-3+6)-(-5-8)+14+3=$$

Evaluate

$40$

Solution Steps

Subtract $3$ from $7$ to get $4$.

$$4+6-\left(-5-8\right)+14+3$$

Add $4$ and $6$ to get $10$.

$$10-\left(-5-8\right)+14+3$$

Subtract $8$ from $-5$ to get $-13$.

$$10-\left(-13\right)+14+3$$

The opposite of $-13$ is $13$.

$$10+13+14+3$$

Add $10$ and $13$ to get $23$.

$$23+14+3$$

Add $23$ and $14$ to get $37$.

$$37+3$$

Add $37$ and $3$ to get $40$.

$$40$$

Factor

$2^{3}\times 5$