$$(7+4 \sqrt{ 3 } + \frac{ 1 }{ 7+4 \sqrt{ 3 } }$$
$14$
$$7+4\sqrt{3}+\frac{7-4\sqrt{3}}{\left(7+4\sqrt{3}\right)\left(7-4\sqrt{3}\right)}$$
$$7+4\sqrt{3}+\frac{7-4\sqrt{3}}{7^{2}-\left(4\sqrt{3}\right)^{2}}$$
$$7+4\sqrt{3}+\frac{7-4\sqrt{3}}{49-\left(4\sqrt{3}\right)^{2}}$$
$$7+4\sqrt{3}+\frac{7-4\sqrt{3}}{49-4^{2}\left(\sqrt{3}\right)^{2}}$$
$$7+4\sqrt{3}+\frac{7-4\sqrt{3}}{49-16\left(\sqrt{3}\right)^{2}}$$
$$7+4\sqrt{3}+\frac{7-4\sqrt{3}}{49-16\times 3}$$
$$7+4\sqrt{3}+\frac{7-4\sqrt{3}}{49-48}$$
$$7+4\sqrt{3}+\frac{7-4\sqrt{3}}{1}$$
$$7+4\sqrt{3}+7-4\sqrt{3}$$
$$14+4\sqrt{3}-4\sqrt{3}$$
$$14$$
Show Solution
Hide Solution
$2\times 7$
