Solve (7 + 7i) + i(7 + 7i) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(7+7i)+i(7+7i)$$

Evaluate

$14i$

Solution Steps

Multiply $i$ times $7+7i$.

$$7+7i+7i+7i^{2}$$

By definition, $i^{2}$ is $-1$.

$$7+7i+7i+7\left(-1\right)$$

Do the multiplications in $7i+7\left(-1\right)$. Reorder the terms.

$$7+7i+\left(-7+7i\right)$$

Combine the real and imaginary parts.

$$7-7+\left(7+7\right)i$$

Do the additions.

$$14i$$

Real Part

$0$

Solution Steps

Multiply $i$ times $7+7i$.

$$Re(7+7i+7i+7i^{2})$$

By definition, $i^{2}$ is $-1$.

$$Re(7+7i+7i+7\left(-1\right))$$

Do the multiplications in $7i+7\left(-1\right)$. Reorder the terms.

$$Re(7+7i+\left(-7+7i\right))$$

Combine the real and imaginary parts in $7+7i-7+7i$.

$$Re(7-7+\left(7+7\right)i)$$

Do the additions in $7-7+\left(7+7\right)i$.

$$Re(14i)$$

The real part of $14i$ is $0$.

$$0$$