How to solve (7a-b)(7a+b)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (7a-b)(7a+b) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(7a-b)(7a+b)$$

Evaluate

$49a^{2}-b^{2}$

Solution Steps

Multiplication can be transformed into difference of squares using the rule: $\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$.

$$\left(7a\right)^{2}-b^{2}$$

Expand $\left(7a\right)^{2}$.

$$7^{2}a^{2}-b^{2}$$

Calculate $7$ to the power of $2$ and get $49$.

$$49a^{2}-b^{2}$$

Show Solution

Expand

$49a^{2}-b^{2}$

Solution Steps

Multiplication can be transformed into difference of squares using the rule: $\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$.

$$\left(7a\right)^{2}-b^{2}$$

Expand $\left(7a\right)^{2}$.

$$7^{2}a^{2}-b^{2}$$

Calculate $7$ to the power of $2$ and get $49$.

$$49a^{2}-b^{2}$$

Show Solution

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Question

Evaluate

Solution Steps

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Solution Steps