Question

$$(8 \frac{ 3 }{ 4 } +14 \frac{ 1 }{ 2 } )(x+3)=66-1$$

Answer

x=2

Solution


Use this rule: \(a \times \frac{b}{c}=\frac{ab}{c}\).
\[(\frac{8\times 3}{4}+14\times \frac{1}{2})(x+3)=66-1\]
Simplify  \(8\times 3\)  to  \(24\).
\[(\frac{24}{4}+14\times \frac{1}{2})(x+3)=66-1\]
Simplify  \(\frac{24}{4}\)  to  \(6\).
\[(6+14\times \frac{1}{2})(x+3)=66-1\]
Simplify  \(14\times \frac{1}{2}\)  to  \(\frac{14}{2}\).
\[(6+\frac{14}{2})(x+3)=66-1\]
Simplify  \(\frac{14}{2}\)  to  \(7\).
\[(6+7)(x+3)=66-1\]
Simplify  \(6+7\)  to  \(13\).
\[13(x+3)=66-1\]
Simplify  \(66-1\)  to  \(65\).
\[13(x+3)=65\]
Divide both sides by \(13\).
\[x+3=\frac{65}{13}\]
Simplify  \(\frac{65}{13}\)  to  \(5\).
\[x+3=5\]
Subtract \(3\) from both sides.
\[x=5-3\]
Simplify  \(5-3\)  to  \(2\).
\[x=2\]