How to solve (8-12+24-32+16-8)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (8-12+24-32+16-8) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(8-12+24-32+16-8)$$

Evaluate

$-4$

Solution Steps

Subtract $12$ from $8$ to get $-4$.

$$-4+24-32+16-8$$

Add $-4$ and $24$ to get $20$.

$$20-32+16-8$$

Subtract $32$ from $20$ to get $-12$.

$$-12+16-8$$

Add $-12$ and $16$ to get $4$.

$$4-8$$

Subtract $8$ from $4$ to get $-4$.

$$-4$$

Show Solution

Factor

$-4$

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