How to solve (8 - sqrt(7)) ^ 2

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (8 - sqrt(7)) ^ 2 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(8-\sqrt{7})^{2}$$

Evaluate

$71-16\sqrt{7}\approx 28.667979023$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(8-\sqrt{7}\right)^{2}$.

$$64-16\sqrt{7}+\left(\sqrt{7}\right)^{2}$$

The square of $\sqrt{7}$ is $7$.

$$64-16\sqrt{7}+7$$

Add $64$ and $7$ to get $71$.

$$71-16\sqrt{7}$$

Show Solution

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$71-16\sqrt{7}$

Solution Steps

Use binomial theorem $\left(a-b\right)^{2}=a^{2}-2ab+b^{2}$ to expand $\left(8-\sqrt{7}\right)^{2}$.

$$64-16\sqrt{7}+\left(\sqrt{7}\right)^{2}$$

The square of $\sqrt{7}$ is $7$.

$$64-16\sqrt{7}+7$$

Add $64$ and $7$ to get $71$.

$$71-16\sqrt{7}$$

Show Solution

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Evaluate

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Solution Steps