1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$( 8 + \sqrt { 5 } ) ( 8 - \sqrt { 5 } )$$

Evaluate

$59$

Solution Steps

Multiplication can be transformed into difference of squares using the rule: $\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$.

$$8^{2}-\left(\sqrt{5}\right)^{2}$$

Calculate $8$ to the power of $2$ and get $64$.

$$64-\left(\sqrt{5}\right)^{2}$$

The square of $\sqrt{5}$ is $5$.

$$64-5$$

Subtract $5$ from $64$ to get $59$.

$$59$$

Show Solution

Factor

$59$

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