$$(8^{0}+4^{-1})\times2^{2}$$
$5$
$$\left(1+4^{-1}\right)\times 2^{2}$$
$$\left(1+\frac{1}{4}\right)\times 2^{2}$$
$$\frac{5}{4}\times 2^{2}$$
$$\frac{5}{4}\times 4$$
$$5$$
Show Solution
Hide Solution
