$$(80b^{3}-180b^{2}+170b-66)\div(10b-10)$$
$\frac{40b^{3}-90b^{2}+85b-33}{5\left(b-1\right)}$
$$\frac{2\left(40b^{3}-90b^{2}+85b-33\right)}{10\left(b-1\right)}$$
$$\frac{40b^{3}-90b^{2}+85b-33}{5\left(b-1\right)}$$
$$\frac{40b^{3}-90b^{2}+85b-33}{5b-5}$$
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