How to solve (8x ^ 2 - 4x ^ 3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (8x ^ 2 - 4x ^ 3) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(8x^{2}-4x^{3})$$

Factor

$4\left(2-x\right)x^{2}$

Solution Steps

Factor out $4$.

$$4\left(2x^{2}-x^{3}\right)$$

Consider $2x^{2}-x^{3}$. Factor out $x^{2}$.

$$x^{2}\left(2-x\right)$$

Rewrite the complete factored expression.

$$4x^{2}\left(-x+2\right)$$

Show Solution

Evaluate

$4\left(2-x\right)x^{2}$

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