$$(9 { x }^{ 3 } -21 { x }^{ 2 } y+16x { y }^{ 2 } -4 { y }^{ 3 } ) \div (x-y)$$
$\left(3x-2y\right)^{2}$
$$\frac{\left(x-y\right)\left(3x-2y\right)^{2}}{x-y}$$
$$\left(3x-2y\right)^{2}$$
$$9x^{2}-12xy+4y^{2}$$
Show Solution
Hide Solution
$9x^{2}-12xy+4y^{2}$
