$$[(9-4) \div 5+(10-2)-4]+9 \times 6 \div 18+2$$
$10$
$$\frac{5}{5}+10-2-4+\frac{9\times 6}{18}+2$$
$$1+10-2-4+\frac{9\times 6}{18}+2$$
$$11-2-4+\frac{9\times 6}{18}+2$$
$$9-4+\frac{9\times 6}{18}+2$$
$$5+\frac{9\times 6}{18}+2$$
$$5+\frac{54}{18}+2$$
$$5+3+2$$
$$8+2$$
$$10$$
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$2\times 5$
