How to solve (9-4+2)-1+(9+5-3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (9-4+2)-1+(9+5-3) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(9-4+2)-1+(9+5-3)$$

Evaluate

$17$

Solution Steps

Subtract $4$ from $9$ to get $5$.

$$5+2-1+9+5-3$$

Add $5$ and $2$ to get $7$.

$$7-1+9+5-3$$

Subtract $1$ from $7$ to get $6$.

$$6+9+5-3$$

Add $6$ and $9$ to get $15$.

$$15+5-3$$

Add $15$ and $5$ to get $20$.

$$20-3$$

Subtract $3$ from $20$ to get $17$.

$$17$$

Show Solution

Factor

$17$

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