$$(9^{-1}-10^{-1})\div45^{-1}$$
$\frac{1}{2}=0.5$
$$\frac{\frac{1}{9}-10^{-1}}{45^{-1}}$$
$$\frac{\frac{1}{9}-\frac{1}{10}}{45^{-1}}$$
$$\frac{\frac{1}{90}}{45^{-1}}$$
$$\frac{\frac{1}{90}}{\frac{1}{45}}$$
$$\frac{1}{90}\times 45$$
$$\frac{1}{2}$$
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$\frac{1}{2} = 0.5$
