How to solve (9s + 27s ^ 3)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (9s + 27s ^ 3) | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(9s+27s^{3})$$

Factor

$9s\left(3s^{2}+1\right)$

Solution Steps

Factor out $9$.

$$9\left(s+3s^{3}\right)$$

Consider $s+3s^{3}$. Factor out $s$.

$$s\left(1+3s^{2}\right)$$

Rewrite the complete factored expression. Polynomial $1+3s^{2}$ is not factored since it does not have any rational roots.

$$9s\left(1+3s^{2}\right)$$

Show Solution

Evaluate

$27s^{3}+9s$

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