$$(a+b+c)^{100}; a=1,b=2,c=-3$$
$d=0$
$$d=\left(1+2-3\right)^{100}$$
$$d=\left(3-3\right)^{100}$$
$$d=0^{100}$$
$$d=0$$
$$a=1$$ $$b=2$$ $$c=-3$$ $$d=0$$
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