Question

$$(\alpha+\frac{1}{\alpha^{9}})^{n}$$

Answer

$$(a^2*l*p*h+1/(a^10*l*p*h))^n$$

Solution


Regroup terms.
\[{(alpha+\frac{1}{a{a}^{9}lph})}^{n}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{(alpha+\frac{1}{{a}^{1+9}lph})}^{n}\]
Simplify  \(1+9\)  to  \(10\).
\[{(alpha+\frac{1}{{a}^{10}lph})}^{n}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{({a}^{2}lph+\frac{1}{{a}^{10}lph})}^{n}\]