Solve (a^ 2 +b^ 2 +2a.b)-(a^ 2 +b^ 2 -2ab) | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$(a^{2}+b^{2}+2a.b)-(a^{2}+b^{2}-2ab)$$

Evaluate

$4ab$

Solution Steps

To find the opposite of $a^{2}+b^{2}-2ab$, find the opposite of each term.

$$a^{2}+b^{2}+2ab-a^{2}-b^{2}+2ab$$

Combine $a^{2}$ and $-a^{2}$ to get $0$.

$$b^{2}+2ab-b^{2}+2ab$$

Combine $b^{2}$ and $-b^{2}$ to get $0$.

$$2ab+2ab$$

Combine $2ab$ and $2ab$ to get $4ab$.

$$4ab$$

Expand

$4ab$

Solution Steps

To find the opposite of $a^{2}+b^{2}-2ab$, find the opposite of each term.

$$a^{2}+b^{2}+2ab-a^{2}-b^{2}+2ab$$

Combine $a^{2}$ and $-a^{2}$ to get $0$.

$$b^{2}+2ab-b^{2}+2ab$$

Combine $b^{2}$ and $-b^{2}$ to get $0$.

$$2ab+2ab$$

Combine $2ab$ and $2ab$ to get $4ab$.

$$4ab$$